How to submit form data use php and ajax ?

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HTML CODE )

<!DOCTYPE html>
<html>
<head>
<title>Submit Form Using AJAX and jQuery</title>
<script src=”http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js”></script>
<link href=”css/refreshform.css” rel=”stylesheet”>
<script src=”script.js”></script>
</head>
<body>
<div id=”mainform”>
<h2> Form Submit Using AJAX and jQuery</h2> <!– Required div Starts Here –>
<div id=”form”>
<h3>Fill Detail !</h3>
<div>
<label>Name :</label>
<input id=”name” type=”text”>
<label>Email :</label>
<input id=”email” type=”text”>
<label>Password :</label>
<input id=”password” type=”password”>
<label>Contact No :</label>
<input id=”contact” type=”text”>
<input id=”submit” type=”button” value=”Submit”>
</div>
</div>
</div>
</body>
</html>
SCRIPT )
$(document).ready(function(){
$(“#submit”).click(function(){
var name = $(“#name”).val();
var email = $(“#email”).val();
var password = $(“#password”).val();
var contact = $(“#contact”).val();
// Returns successful data submission message when the entered information is stored in database.
var dataString = ‘name1=’+ name + ‘&email1=’+ email + ‘&password1=’+ password + ‘&contact1=’+ contact;
if(name==”||email==”||password==”||contact==”)
{
alert(“Please Fill All Fields”);
}
else
{
// AJAX Code To Submit Form.
$.ajax({
type: “POST”,
url: “ajaxsubmit.php”,
data: dataString,
cache: false,
success: function(result){
alert(result);
}
});
}
return false;
});
});

AJAXSUBMIT.PHP )
<?php
$connection = mysql_connect(“localhost”, “root”, “”); // Establishing Connection with Server..
$db = mysql_select_db(“mydba”, $connection); // Selecting Database
//Fetching Values from URL
$name2=$_POST[‘name1’];
$email2=$_POST[’email1′];
$password2=$_POST[‘password1’];
$contact2=$_POST[‘contact1’];
//Insert query
$query = mysql_query(“insert into form_element(name, email, password, contact) values (‘$name2’, ‘$email2’, ‘$password2′,’$contact2’)”);
echo “Form Submitted Succesfully”;
mysql_close($connection); // Connection Closed
?>






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